8m^2-65m+8=0

Solution for 8m^2-65m+8=0 equation:

8m^2-65m+8=0

a = 8; b = -65; c = +8;
Δ = b2-4ac
Δ = -652-4·8·8
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-63}{2*8}=\frac{2}{16}
=1/8
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+63}{2*8}=\frac{128}{16}
=8
$